select c.categories_id, cd.categories_name, c.parent_id from categories c, categories_description cd where c.categories_id = cd.categories_id and cd.language_id = '1' and c.parent_id = '675' order by c.sort_order, cd.categories_name [TEP STOP] 2006 - MySQL server has gone away select count(*) as total from sessions where sesskey = '79d20d0fb18705f653a8034dfcf4d78e' [TEP STOP] |