select c.categories_id, cd.categories_name, c.parent_id from categories c, categories_description cd where c.categories_id = cd.categories_id and cd.language_id = '1' and c.parent_id = '51' order by c.sort_order, cd.categories_name [TEP STOP] 2006 - MySQL server has gone away select count(*) as total from sessions where sesskey = 'c5d6f6e1f2867c6d4d1775b278ddb145' [TEP STOP] |